两个date之间的Android差异

我有两个date,如:

String date_1="yyyyMMddHHmmss"; String date_2="yyyyMMddHHmmss"; 

我想要打印的差异,如:

 2d 3h 45m 

我怎样才能做到这一点? 谢谢!

Solutions Collecting From Web of "两个date之间的Android差异"

 DateTimeUtils obj = new DateTimeUtils(); SimpleDateFormat simpleDateFormat = new SimpleDateFormat("dd/M/yyyy hh:mm:ss"); try { Date date1 = simpleDateFormat.parse("10/10/2013 11:30:10"); Date date2 = simpleDateFormat.parse("13/10/2013 20:35:55"); obj.printDifference(date1, date2); } catch (ParseException e) { e.printStackTrace(); } //1 minute = 60 seconds //1 hour = 60 x 60 = 3600 //1 day = 3600 x 24 = 86400 public void printDifference(Date startDate, Date endDate) { //milliseconds long different = endDate.getTime() - startDate.getTime(); System.out.println("startDate : " + startDate); System.out.println("endDate : "+ endDate); System.out.println("different : " + different); long secondsInMilli = 1000; long minutesInMilli = secondsInMilli * 60; long hoursInMilli = minutesInMilli * 60; long daysInMilli = hoursInMilli * 24; long elapsedDays = different / daysInMilli; different = different % daysInMilli; long elapsedHours = different / hoursInMilli; different = different % hoursInMilli; long elapsedMinutes = different / minutesInMilli; different = different % minutesInMilli; long elapsedSeconds = different / secondsInMilli; System.out.printf( "%d days, %d hours, %d minutes, %d seconds%n", elapsedDays, elapsedHours, elapsedMinutes, elapsedSeconds); } 

输出是:

 startDate : Thu Oct 10 11:30:10 SGT 2013 endDate : Sun Oct 13 20:35:55 SGT 2013 different : 291945000 3 days, 9 hours, 5 minutes, 45 seconds 

这工作,并转换为string作为奖金;)

 protected void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.activity_main); try { //Dates to compare String CurrentDate= "09/24/2015"; String FinalDate= "09/26/2015"; Date date1; Date date2; SimpleDateFormat dates = new SimpleDateFormat("MM/dd/yyyy"); //Setting dates date1 = dates.parse(CurrentDate); date2 = dates.parse(FinalDate); //Comparing dates long difference = Math.abs(date1.getTime() - date2.getTime()); long differenceDates = difference / (24 * 60 * 60 * 1000); //Convert long to String String dayDifference = Long.toString(differenceDates); Log.e("HERE","HERE: " + dayDifference); } catch (Exception exception) { Log.e("DIDN'T WORK", "exception " + exception); } } 

它会给你几个月的差异

 long milliSeconds1 = calendar1.getTimeInMillis(); long milliSeconds2 = calendar2.getTimeInMillis(); long periodSeconds = (milliSeconds2 - milliSeconds1) / 1000; long elapsedDays = periodSeconds / 60 / 60 / 24; System.out.println(String.format("%d months", elapsedDays/30)); 
 Date userDob = new SimpleDateFormat("yyyy-MM-dd").parse(dob); Date today = new Date(); long diff = today.getTime() - userDob.getTime(); int numOfDays = (int) (diff / (1000 * 60 * 60 * 24)); int hours = (int) (diff / (1000 * 60 * 60)); int minutes = (int) (diff / (1000 * 60)); int seconds = (int) (diff / (1000)); 
 DateTime start = new DateTime(2013, 10, 20, 5, 0, 0, Locale); DateTime end = new DateTime(2013, 10, 21, 13, 0, 0, Locale); Days.daysBetween(start.toLocalDate(), end.toLocalDate()).getDays() 

它会返回给定的两个date之间多less天,其中DateTime来自joda库

短而甜:

 /** * Get a diff between two dates * * @param oldDate the old date * @param newDate the new date * @return the diff value, in the days */ public static long getDateDiff(SimpleDateFormat format, String oldDate, String newDate) { try { return TimeUnit.DAYS.convert(format.parse(newDate).getTime() - format.parse(oldDate).getTime(), TimeUnit.MILLISECONDS); } catch (Exception e) { e.printStackTrace(); return 0; } } 

用法:

 int dateDifference = (int) getDateDiff(new SimpleDateFormat("dd/MM/yyyy"), "29/05/2017", "31/05/2017"); System.out.println("dateDifference: " + dateDifference); 

输出:

 dateDifference: 2 

你可以把它推广到一个让你select输出格式的函数

 private String substractDates(Date date1, Date date2, SimpleDateFormat format) { long restDatesinMillis = date1.getTime()-date2.getTime(); Date restdate = new Date(restDatesinMillis); return format.format(restdate); } 

现在是这样一个简单的函数调用,小时,分钟和秒的差异:

 SimpleDateFormat formater = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss"); try { Date date1 = formater.parse(dateEnd); Date date2 = formater.parse(dateInit); String result = substractDates(date1, date2, new SimpleDateFormat("HH:mm:ss")); txtTime.setText(result); } catch (ParseException e) { e.printStackTrace(); } 

您可以使用此方法计算以毫秒为单位的时间差,并以秒,分,小时,天,月和年获得输出。

你可以从这里下载类: DateTimeDifference GitHub链接

  • 简单易用
  long currentTime = System.currentTimeMillis();
 long previousTime =(System.currentTimeMillis() -  864000000);  // 10天前

 Log.d(“DateTime:”,“与第二个差异:”+ AppUtility.DateTimeDifference(currentTime,previousTime,AppUtility.TimeDifference.SECOND));
 Log.d(“DateTime:”,“与分钟差异:”+ AppUtility.DateTimeDifference(currentTime,previousTime,AppUtility.TimeDifference.MINUTE)); 
  • 你可以比较下面的例子
  if(AppUtility.DateTimeDifference(currentTime,previousTime,AppUtility.TimeDifference.MINUTE)> 100){
     Log.d(“DateTime:”,“两个date之间有超过100分钟的差异”);
 }其他{
     Log.d(“DateTime:”,“两个date之间不超过100分钟的差异”);
 } 

当您使用Date()来计算以小时为单位的差异时,必须以UTCconfigurationSimpleDateFormat() ,否则由于Daylight SavingTime会出现一小时的错误。

我用这个:以毫秒为单位发送开始和结束date

 public int GetDifference(long start,long end){ Calendar cal = Calendar.getInstance(); cal.setTimeInMillis(start); int hour = cal.get(Calendar.HOUR_OF_DAY); int min = cal.get(Calendar.MINUTE); long t=(23-hour)*3600000+(59-min)*60000; t=start+t; int diff=0; if(end>t){ diff=(int)((end-t)/ TimeUnit.DAYS.toMillis(1))+1; } return diff; } 

这是现代的答案。 对于任何使用Java 8或更高版本(对大多数Android手机都不适用)或对外部库感到满意的用户来说,这是一件好事。

  String date1 = "20170717141000"; String date2 = "20170719175500"; DateTimeFormatter formatter = DateTimeFormatter.ofPattern("yyyyMMddHHmmss"); Duration diff = Duration.between(LocalDateTime.parse(date1, formatter), LocalDateTime.parse(date2, formatter)); if (diff.isZero()) { System.out.println("0m"); } else { long days = diff.toDays(); if (days != 0) { System.out.print("" + days + "d "); diff = diff.minusDays(days); } long hours = diff.toHours(); if (hours != 0) { System.out.print("" + hours + "h "); diff = diff.minusHours(hours); } long minutes = diff.toMinutes(); if (minutes != 0) { System.out.print("" + minutes + "m "); diff = diff.minusMinutes(minutes); } long seconds = diff.getSeconds(); if (seconds != 0) { System.out.print("" + seconds + "s "); } System.out.println(); } 

这打印

 2d 3h 45m 

在我看来,优点不在于它比较短(不是很多),而是将计算结果保存到一个标准的库中,这样做可以减less错误的发生,并且使代码更加清晰。 这些是很大的优点。 读者不需要承认像24,60和1000这样的常量,并validation它们的使用是否正确。

我正在使用现代化的Javadate和时间API(在JSR-310中进行了介绍,并且以该名称为人所知)。 在Android上使用这个,得到ThreeTenABP,看到这个问题:如何在Android项目中使用ThreeTenABP 。 要与其他Java 6或7一起使用,请获取ThreeTen Backport 。 对于Java 8及更高版本,它是内置的。

对于Java 9来说,它会更容易一些,因为Duration类是通过扩展方法来分别给出部分,小时部分,分钟部分和秒部分,所以你不需要减法。 在我的答案在这里看到一个例子。