什么是命名空间,肥皂行动和url应该是我的Android应用程序访问WCF Web服务?

我的WSDL是这样的:

<?xml version="1.0" encoding="utf-8"?> <wsdl:definitions name="ABCWcfService" targetNamespace="http://www.ABC.com/ABCWcfService" xmlns:wsdl="http://schemas.xmlsoap.org/wsdl/" xmlns:wsx="http://schemas.xmlsoap.org/ws/2004/09/mex" xmlns:wsa10="http://www.w3.org/2005/08/addressing" xmlns:tns="http://www.ABC.com/ABCWcfService" xmlns:soap12="http://schemas.xmlsoap.org/wsdl/soap12/" xmlns:wsu="http://docs.oasis-open.org/wss/2004/01/oasis-200401-wss-wssecurity-utility-1.0.xsd" xmlns:wsp="http://schemas.xmlsoap.org/ws/2004/09/policy" xmlns:wsap="http://schemas.xmlsoap.org/ws/2004/08/addressing/policy" xmlns:msc="http://schemas.microsoft.com/ws/2005/12/wsdl/contract" xmlns:wsa="http://schemas.xmlsoap.org/ws/2004/08/addressing" xmlns:wsam="http://www.w3.org/2007/05/addressing/metadata" xmlns:wsaw="http://www.w3.org/2006/05/addressing/wsdl" xmlns:soap="http://schemas.xmlsoap.org/wsdl/soap/" xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns:soapenc="http://schemas.xmlsoap.org/soap/encoding/"> <wsdl:types> <xsd:schema targetNamespace="http://www.ABC.com/ABCWcfService/Imports"> <xsd:import schemaLocation="http://desktop/ABCWcfService/ABCWcfService.svc?xsd=xsd0" namespace="http://www.ABC.com/ABCWcfService"/> <xsd:import schemaLocation="http://desktop/ABCWcfService/ABCWcfService.svc?xsd=xsd1" namespace="http://schemas.microsoft.com/2003/10/Serialization/"/> </xsd:schema> </wsdl:types> <wsdl:message name="IABCWcfService_GetWhatsOnData_InputMessage"> <wsdl:part name="parameters" element="tns:GetWhatsOnData"/> </wsdl:message> <wsdl:message name="IABCWcfService_GetWhatsOnData_OutputMessage"> <wsdl:part name="parameters" element="tns:GetWhatsOnDataResponse"/> </wsdl:message> <wsdl:portType name="IABCWcfService"> <wsdl:operation name="GetWhatsOnData"> <wsdl:input wsaw:Action="http://www.ABC.com/ABCWcfService/IABCWcfService/GetWhatsOnData" message="tns:IABCWcfService_GetWhatsOnData_InputMessage"/> <wsdl:output wsaw:Action="http://www.ABC.com/ABCWcfService/IABCWcfService/GetWhatsOnDataResponse" message="tns:IABCWcfService_GetWhatsOnData_OutputMessage"/> </wsdl:operation> </wsdl:portType> <wsdl:binding name="BasicHttpBinding_IABCWcfService" type="tns:IABCWcfService"> <soap:binding transport="http://schemas.xmlsoap.org/soap/http"/> <wsdl:operation name="GetWhatsOnData"> <soap:operation soapAction="http://www.ABC.com/ABCWcfService/IABCWcfService/GetWhatsOnData" style="document"/> <wsdl:input> <soap:body use="literal"/> </wsdl:input> <wsdl:output> <soap:body use="literal"/> </wsdl:output> </wsdl:operation> </wsdl:binding> <wsdl:service name="ABCWcfService"> <wsdl:port name="BasicHttpBinding_IABCWcfService" binding="tns:BasicHttpBinding_IABCWcfService"> <soap:address location="http://desktop/ABCWcfService/ABCWcfService.svc"/> </wsdl:port> </wsdl:service> </wsdl:definitions> 

我想知道我应该为我的SOAP_ACTION,METHOD_NAME,NAMESPACE和URL? 我猜:

 SOAP_ACTION = "http://www.ABC.com/ABCWcfService/IABCWcfService/GetWhatsOnData" METHOD_NAME = "GetWhatsOnData" NAMESPACE = "http://www.ABC.com/ABCWcfService" URL = "http://desktop/ABCWcfService/ABCWcfService.svc" 

但它似乎不工作在我的代码:

 SoapObject request = new SoapObject(NAMESPACE, METHOD_NAME); SoapSerializationEnvelope envelope = new SoapSerializationEnvelope(SoapEnvelope.VER11); envelope.dotNet = true; envelope.setOutputSoapObject(request); HttpTransportSE androidHttpTransport = new HttpTransportSE(URL); androidHttpTransport.call(SOAP_ACTION, envelope); SoapObject result = (SoapObject) envelope.getResponse(); 

它在行androidHttpTransport.call(SOAP_ACTION,信封); exception对象e的值为null。

我有补充

 <uses-permission android:name="android.permission.INTERNET"></uses-permission> 

在Manifest文件中

谁能告诉我什么是错的?

非常感谢你。

Solutions Collecting From Web of "什么是命名空间,肥皂行动和url应该是我的Android应用程序访问WCF Web服务?"

您可以使用WCFTestClient并单击底部的XML选项卡。 你可以find你正在寻找的信息(SOAP URL和Action)。 我希望这将有所帮助。

以及即时通讯这样做

 [OperationContract] [WebInvoke(Method = "GET", RequestFormat = WebMessageFormat.Json, ResponseFormat = WebMessageFormat.Json, UriTemplate = "/Login?ID={ID}&PASSWORD={PASSWORD}")] System.IO.Stream ValidarLogin(int ID, string PASSWORD); 

并在Android客户端

 class MiTareaAsincrona extends AsyncTask<Void, Integer, String> { ProgressDialog dialog=null; protected void onPreExecute() { dialog = new ProgressDialog(MainScreen.this); dialog.setMessage("Verificando sus datos.. "); dialog.setProgressStyle(ProgressDialog.STYLE_SPINNER); // dialog.setMax(100); dialog.setCancelable(false); dialog.show(); } @Override protected String doInBackground(Void... params) { final EditText text1 = (EditText) findViewById(R.id.editText1); final EditText text2 = (EditText) findViewById(R.id.editText2); String Cedula= text1.getText().toString(); String Password = text2.getText().toString(); final String URL = "https://MYURL.COM/NGLOGIN/NGLogin.svc/Login?ID="+Cedula+"&PASSWORD="+Password; if(!Cedula.equals("") || !Password.equals("")){ try { key=ValidarLogin(URL); } catch (ClientProtocolException e) { // TODO Auto-generated catch block e.printStackTrace(); } catch (IOException e) { // TODO Auto-generated catch block e.printStackTrace(); key="noinet"; } catch (JSONException e) { // TODO Auto-generated catch block e.printStackTrace(); } // this.cancel(true); } return key; } @Override protected void onPostExecute(String result) { String a= result.toString(); Boolean aa= " ".equals(result); if(!result.equals("false") & !result.equals("noinet")){ dialog.dismiss(); finalizo=true; if(finalizo){ Intent intent = new Intent(getApplicationContext(), MainMenu.class); intent.putExtra("llave", key); startActivity(intent);} 

ValidarLogin(URL)代码:

 public String ValidarLogin (String URL) throws ClientProtocolException, IOException, JSONException { Security.addProvider(new BouncyCastleProvider()); HttpClient client = new MyHttpsClient(getApplicationContext()); HttpGet get = new HttpGet(URL); HttpResponse response = client.execute(get); int status = response.getStatusLine().getStatusCode(); if(status == 200) //sucess { HttpEntity e = response.getEntity(); String key = EntityUtils.toString(e); // get.abort(); /*/ char[] arreglo = key.toCharArray(); char[] arreglo2= new char[arreglo.length-2]; for(int x=1; x<arreglo.length-1;x++){ arreglo2[x-1] = arreglo[x]; } /*/ if(!key.equals("")){return key;} return "false"; } return "false"; } 

如果用户和密码正确,则wcf将返回1或不返回任何内容。

希望这可以帮助你